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A resistorand a capacitorare connected in seriesto a 50 Hz acsource . Thevoltage(rms ) acroossthe resistorand capacitorare 151 Vand 160.3 VrespectivelyCalculatethe rmsvoltageof thesource.Alsofindthe capactivereactanceadnimpedanceof thecircuit, if thecircuitis 0.755 A . |
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Answer» SOLUTION :`V_R =151 V ,V_C=160.3V` `V_(rms) = sqrt(V_(R)^(2) +V_(C)^(2))` `= sqrt((151)^2 +(160 .3)^2)` ` V_(rms) = 220V ` Capacitivereactance : `V_C =I X_C` `X_C= (V_C)/(I ) = (160.3)/(0.755 )` ` X_C = 212.31 OMEGA ` impedance : ` Z=(V_(rms))/(I )= (220 )/(0.755)` `Z = 291.39Omega ` |
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