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A reversibleheatengine A(basedon carnot cycle ) absorbs heat froma reservoirat 1000 Kand rejects heatto a reservoir at T_(2). A secondreversibleengine B absorbs, the sameamountof heatas rejected by the engine A, from thereservoir at T_(2) and rejectsenergytoa reservoir at 360 K.If the efficienicesof engines A and B are thesame then thetemperature T_(2) is .

Answer»

680 K
640 K
600 K
none

SOLUTION :For heatengines A:`eta= (1000- T_(2))/(1000) rArreta_(B) = (T_(2) - 360)/(T_(2))`
`eta_(A) = eta_(B)`
`So(1000-T_(2))/(1000)=(T_(2) - 360)/(T_(2)) = T_(2) = sqrt(360 xx 1000)=600 K`


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