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A reversibleheatengine A(basedon carnot cycle ) absorbs heat froma reservoirat 1000 K and rejects heat to a reservoirat T_(2) . A secondreserviour at T_(2) and rejects energy to areservoirat360 K .If the efficienciesof engines A and Bare thesame then the temperature T_(2)is . |
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Answer» 680 K `eta_(1)= 1- (T_(2))/(1000)` For B `eta_(2) = 1-(360)/(T_(2))` `1- (T_(2))/(1000)= 1 -(360)/(T_(2))` `T_(2)= 600K` |
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