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A rigid circular loop of radius r and mass m lies in the XY plane on a flat table and has a current I flowering in it. At this particular place, the earth's magnetic field is vecB = B_x hati + B_z hatk . The value of I so that one end of the loop lifts from the table is |
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Answer» `(mg)/( pi R SQRT(B_(X)^(2) +B_(Z)^(2)))` |
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