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A ring angled isosceles prism KLM of refractive index n_(1) is placed inside a rectangular block PQRS of refractive index n_(2) as shown in the adjoining Fig. The rectangular box is surrounded by a medium of refractive index n_(3). A ray of light AB enters the rectangular block normally. Depending upon the relationships between n_(1), n_(2) and n_(3). it takes one of the four possible paths. What is the condition for light ray to proceed along the path no. 4 (i.e., path ABCEF)? |
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Answer» Solution :The ray no. 4 bends towards normal while undergoing REFRACTION at C. So we conclude that `n_(2) gt n_(1)`. HOWEVER, while undergoing refraction at E the ray bends away from the normal. Hence `n_(3) LT n_(2)`. So this situation is possible only if `n_(2) gt n_(1) and n_(2) gt n_(3)`. |
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