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A ring consisting of two parts `ADB` and `ACB` of same conductivity k carries an amount of heat `H` The `ADB` part is now replaced with another metal keeping the temperature `T_91)` and `T_(2)` constant The heat carried increases to `2H` What should be the conductivity of the new `ADB` Given `(ACB)/(ADB)=3` .A. `(7)/(3)K`B. `2K`C. `(5)/(2)K`D. `3K` |
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Answer» Correct Answer - A `(dQ)/(dt) = (KA d theta)/("arc length")` . |
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