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A ring is oscillating about a horizontal axis passes through its rim. Determine time period of oscillation. |
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Answer» Solution :For RING `I= MK^2 = MR^2` So, `K= R` `L=l + (K^2)/(l)= R+ (R^2)/(R )= 2R` `T= 2 pi sqrt((2R)/(G))` |
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