1.

A ring is rotating without slipping. The ratio of its translational kinetic energy to the total K.E. is :

Answer»

`1:2`
`2:3`
`3:2`
`2:1`

SOLUTION :Total K.E. = `(1)/(2)MV^(2)+(1)/(2)IOMEGA^(2)=(1)/(2)mv^(2)+(1)/(2)mpi^(2)omega^(2)`
= `(1)/(2)mv^(2)+(1)/(2)mv^(2)=mv^(2)`
`THEREFORE (E_("trans"))/(E_("total"))=((1)/(2)mv^(2))/(mv^(2))=(1)/(2)`


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