A ring of mass m and radius R rests in equilibrium on a smooth cone of semi-vertical angle 45^(@) as shown. The radius of the cone is 2R. the radius of circular crosssection of the ring is r(r lt lt R). What will be the speed of transverse wave on the ring?

A ring of mass m and radius R rests in equilibrium on a smooth cone of

1.	A ring of mass m and radius R rests in equilibrium on a smooth cone of semi-vertical angle 45^(@) as shown. The radius of the cone is 2R. the radius of circular crosssection of the ring is r(r lt lt R). What will be the speed of transverse wave on the ring?
Answer» `SQRT(gR)` `sqrt(2gR)` `(1)/(2)sqrt(gR)` `2sqrt(gR)` Solution :`V= sqrt((T)/(mu))= sqrt((MG)/(2PI ((m)/(2pi R))))=sqrt(gR)`

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A ring of mass m and radius R rests in equilibrium on a smooth cone of semi-vertical angle 45^(@) as shown. The radius of the cone is 2R. the radius of circular crosssection of the ring is r(r lt lt R). What will be the speed of transverse wave on the ring?

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