1.

A ring of mass m and radius r rotates about an axis passing through its centre and perpendicular to its plane with angular velocity omega. Its kinetic energy is

Answer»

`1/2mr^(2)OMEGA^(2)`
`mromega^(2)`
`mr^(2)omega^(2)`
`1/2mromega^(2)`

SOLUTION :KINETIC energy =`1/2Iomega^(2)`, and for ring `I=mr^(2)`. Hence KE `=1/2mr^(2)omega^(2)`


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