1.

A ring of mass m sliding on a smooth surface with velocity v_(0) enters rough surface with coefficient of kinetic friction mu_(k), then

Answer»

the linear distance moved by centre of MASS before the ring starts pure rolling is `(3v_(0)^(2))/(8 mu_(k)g)`
the gain in kinetic energy is `(mv_(0)^(2))/(8)`
the loss in kinetic energy is `(mv_(0)^(2))/(4)`
the work DONE by friction force is `-(3mv_(0)^(2))/(8)`

ANSWER :C


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