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A ring of radius R and linear charge density lambda on its surface is performing rotational motion about an axis perpendicular to its plane. lf the angular velocity of the ring is omega, how much current is constituted by the ring? |
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Answer» R`omega lambda` Linear charge density of electric charge COLLECTED on RING= `lambda` `therefore ` Total charge on ring (Q) =`lambda L = lambda (2 pi R)` As ring rotates at the angular speed ro, let electric CURRENT due to it = I. ` I = (Q)/(l) = (Q)/(T)= (2 pi R lambda)/(T) = (2 pi R lambda)/((2 pi )/(omega))"" (because omega = (2pi)/(T))` I =R `omegalambda ` |
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