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A road roller of length 50m and diameter 120cm is used to level road . How many square meter of area leveled road in 500 revolutions. Also find the cost of repairing the road at the rate of RS 75 per square meter |
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Answer» Area leveled in 500 REVOLUTIONS = 94,200 m².Cost of repairing road = RS. 70,65,000.Step-by-step explanation:Given:Length of road roller = 50 mDiameter of road roller = 120 cm = 1.2 mRadius of road roller = 1.2/2 = 0.6 mRate of repairing the road = Rs. 75 PER m²To FIND:How many m² of area leveled road in 500 revolutions.Find the cost of repairing of road.Formula USED:Curved surface area of circle = 2πrhNow,⇒ Area leveled in one revolution = 2πrh⇒ Area leveled in one revolution = 2 × 3.14 × 0.6 × 50⇒ Area leveled in one revolution = 188.4 m²Now,⇒ Area leveled in 500 revolutions = 188.4 × 500⇒ Area leveled in 500 revolutions = 94,200 m²Hence, Area leveled in 500 revolutions = 94,200 m².Now, ⇒ Cost of repairing the road = Rs. 75 per m².⇒ Cost of repairing the road of 94,200 m² = 75 × 94, 200⇒ Cost of repairing the road of 94,200 m² = Rs. 70,65,000.Hence, cost of repairing road = Rs. 70,65,000. |
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