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A rocket with an initial mass m_(0) is going up with a constant acceleration a by exhausting gases with a velocity v relative to the rocket motion, then the mass of the rocket at any instant of time is (assume that no other forces act on it) |
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Answer» `m=m_(0)e^(-(at)/v)` `m(dv)/(DT)=F_("ext")+v(dm)/(dt)` WITHOUT any EXTERNAL force `(F_("ext")=0)`, `m(dv)/(dt)=v(dm)/(dt)rArrint(dv)/v=int(dm)/m` `rArrlogv=logm+C` When, `v=0,m=m_(0)` `thereforeC=-logm_(0)` So, we have `(Deltav)/v="log"m/m_(0)*dtorm=m_(0)e^(-at//v)` |
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