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A rod CD of length b carryinga current l, isplaced in a magnetic field due to a thin log wire AB carrying currrent I as shown in fig. Then find the net force experienced by the wire |
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Answer» SOLUTION :Magnetic induction due to a straight wire at a position of small ELEMENT in at a DISTANCE x from the conductor `dB=(mu_(0))/(2pi)(I_(1))/x` force on the current element is `vecdF=dBI_(2)dxsin90^(@)` `dF=(mu_(0))/(2pi)(I_(1)I_(2))/xdx` Net force on conductor is `F=int_(a)^(a+b)(mu_(0))/(2pi)(I_(1)I_(2))/xdx` `=(mu_(0))/(2pi)I_(1)I_(2)[logx]_(a)^(a+b)=(mu_(0))/(2pi)I_(1)I_(2)log(1+b/a)` 
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