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A rod is moving with velocity 9 m/s perpendicular to external magnetic field of 1T and there is a conducting sphere having charge 30 C and radius R. If electric field inside rod is same as electric field on the surface of sphere and radius R = x xx 10^(5) m then find x. |
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Answer» electric field on surface of sphere `= (KQ)/(R ^(2))` `(KQ)/(R ^(2)) =-vB IMPLIESR^(2)=(kQ)/(vB) =(9xx10^(9)xx30)/(9xx1)` `R= sqrt3xx10^(5) =1.73 xx10^(5)` |
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