1.

A rod lies along the x-axis with one end at the origin and the other at x rarr oo. It carries a uniform charge lambda C/m. The electric field at the point x = -a on the axis will be

Answer»

`VEC(E) = (LAMBDA)/(4pi epsilon_(0)a)(-hat(i))`
`vec(E) = (lambda)/(4pi epsilon_(0)a)(hat(i))`
`vec(E) = (lambda)/(2pi epsilon_(0)a)(-hat(i))`
`E = (lambda)/(2pi epsilon_(0)a)(hat(i))`

Solution :The ELECTRIC field at the point x = -a on the axis will be `vec(E) = (lambda)/(4pi epsilon_(0)a)(-hat(i))`


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