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A rod mass (M) hinged at (O) is kept in equilibrium with a spring of stiffness (k) as shown in figure. The potential energy stored in the spring is . A. `(mg)^(2)/(4k)`B. `(mg)^(2)/(2k)`C. `(mg)^(2)/(8k)`D. `(mg)^(2)/(k)`. |
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Answer» Correct Answer - C `sum ("Moment about" O)=0` `:. (kx) l = mg (l/2)` or `x=(mg)/(2k)` `U=(1)/(2)kx^(2) =(mg)^(2)/(8k)` |
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