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A rod of 10 cm length is moving perpendicular to uniform magnetic field of intensity 5 xx 10^(-4) "Wb/m"^2. If the acceleration of the rod is 5 "m/s"^2, then the rate of increase of induced emf is …. |
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Answer» `2.5XX10^(-4) Vs^(-1)` `THEREFORE (d|epsilon|)/(DT)=B(dv)/(dt)l` =Bal `=5xx10^(-4)xx5xx0.1` `=2.5xx10^(-4) "Vs"^(-1)` |
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