1.

A rod of 10 cm length is moving perpendicular to uniform magnetic field of intensity 5 xx 10^(-4) "Wb/m"^2. If the acceleration of the rod is 5 "m/s"^2, then the rate of increase of induced emf is ….

Answer»

`2.5XX10^(-4) Vs^(-1)`
`25xx10^(-4)` Vs
`20xx10^(-4)` Vs
`20xx10^(-4) "Vs"^(-1)`

Solution :`|EPSILON|`=Bvl
`THEREFORE (d|epsilon|)/(DT)=B(dv)/(dt)l`
=Bal
`=5xx10^(-4)xx5xx0.1`
`=2.5xx10^(-4) "Vs"^(-1)`


Discussion

No Comment Found

Related InterviewSolutions