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A rod of length 1 is rotated about its one end, perpendicular to a magnetic field of induction B. What is the e.m.f. induced in the rod? |
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Answer» SOLUTION :Induced e.m.f.(e) = `(dphi)/dt` = `B.(DA)/dt` But dA = `pil^2` and dt = T and T = `2pi/w` e = `B.pil^2//(2pi/omega) = `1/2Bl^2omega` |
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