A rod of length 1 m rotates in the xy plane about the fixed point O in the anticlockwise sense, as shown in figure with velocity `omega=a+bt` where `a=10rads^(-1)` and `b=5rads^(-2)`. The velocity and acceleration of the point A at `t=0` isA. `+10hatims^(-1)` and `+5hatims^(-2)`B. `+10hatjms^(-1)` and `(-100hati+5hatj)ms^(-2)`C. `-10hatjms^(-1)` and `(100hati+5hatj)ms^(-2)`D. `-10hatjms^(-1)` and `-5hatjms^(-1)`

A rod of length 1 m rotates in the xy plane about the fixed point O i

1.	A rod of length 1 m rotates in the xy plane about the fixed point O in the anticlockwise sense, as shown in figure with velocity `omega=a+bt` where `a=10rads^(-1)` and `b=5rads^(-2)`. The velocity and acceleration of the point A at `t=0` isA. `+10hatims^(-1)` and `+5hatims^(-2)`B. `+10hatjms^(-1)` and `(-100hati+5hatj)ms^(-2)`C. `-10hatjms^(-1)` and `(100hati+5hatj)ms^(-2)`D. `-10hatjms^(-1)` and `-5hatjms^(-1)`
Answer» `omega=10+5t` `alpha=(domega)/(dt)=5` At `t=0,omega=10rad//s` and `alpha=5rad//s^(2)impliesr=OA=1m` `v=(romega)hatj=(10hatj)m//s` `a=(ralpha)hatj-(romega^(2))hati` `=(-100hati+5hatj)m//s^(2)`

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