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A rod of length 10.0 cm lies along the principal axis of a concav mirror of focal length in such a way that the end closer to the pole is 20.0 cm away from it. The length of the image is : |
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Answer» 10.0 cm  For end M, u = - 30 cm `therefore (1)/(u) + (1)/(V) = (1)/(f)` `therefore (1)/(v) = (1)/(u) - (1)/(u) = (-1)/(10) = (-1)/(15)` `therefore` v = - 15 cm = distance of image of end M. , Thus lenght of image of rod = 20 - 15 = 5 cm. |
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