1.

A rod of length l=100cm is fixed at 30cm from both end. If velocity of transverse wave in rod is v(cms^(-1)), then chose the correct option(s)

Answer»

FUNDAMENTAL FREQUENCEY (in Hz) of transverse wave in rod is `v/40`
Second OVERTONE in rod will `5^(th)` harmonic
Frequency of third overtone (in Hz) is `7v//40`
Third overtone is`5^(th)` harmonic

Solution :`(mlamda)/2=40`
`(n+1/2) (lamda)/2=30`
`((2n+1))/m=6/4implies=m=((2n+1))/3`
`n=1 m=2, lamda=40 cm`
`n=4, m-6, v=flamdaimpliesf//40=f_(0)`
`n=7, m=10`
`lamda=8` second overtone
`n=10m m=14`
`lamda=40/7impliesf_(3)=(7v)/40`


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