1.

A rod of length l is rotated with angular speed omega about an axis passing through the centre of rod and perpendicular to its length. A uniform magnetic field B is applied parallel to the axis of rotation, Potential difference developed between the ends of the rod is

Answer»

`Bl(omega^(2))/(2)`
`Bl(omega^(2))`
`Bl(omega^(2))/(8)`
Zero

Solution :Both ends of rod will ACQUIRE potential of same MAGNITUDE `(Bomegal^(2))/(8)` and POLARITY with RESPECT to the centre of rod and hence there will not be any potential difference between the ends of the rod.


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