1.

A rod of mass M and length L is placed on a smooth horizontal surface. It is hinged at one end so that it can rotate freely in a horizontal circle about this end. There exists a uniform magnetic field vecB perpendicular, into the horizontal surface everywhere. The strength of magnetic field starts varying as B=B_(0)t. (i) Find the torque acting on the rod about its hinged end. (ii) Find the reaction produced at hinge at t = 0. (A charge Q is distributed uniformaly on the rod)

Answer»

SOLUTION :(a) `(QB_(0)L^(2))/(6)`
(b) zero


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