1.

A rope is wound round a hollow cylinder of mass 2 kg and radius 0.5 m. If the rope is pulled with aforce of 80 N, the angular acceleration of the cylinder will be -

Answer»

20 rad/`s^(2)`
40 rad/`s^2 `
60 rad/`s^2 `
80 rad/`s^2 `

Solution :`I=Mr^(2)`
Torqueactingon thecylinderbypullingtheropewitha force Fis
`T=r Fsin theta `
`=F.(rsin theta)=F.r _(1) `
`=80xx0.5 = 40n-m`
`and1=Mr^(2) = 2xx(0.5)^(2)= 0.5 kgm^(2)`
`thereforealpha =( tau)/(I)(40N -m)/(0.5 KG - m^(2))=80 rad //s^(2)`


Discussion

No Comment Found

Related InterviewSolutions