1.

A rotating wheel changes angular speed from 1800 rpm to 3000 rpm in 20 s. What is the angular acceleration assuming to be uniform ?

Answer»

`60pi` rad `s^(-2)`
`90pi` rad `s^(-2)`
`2PI` rad `s^(-2)`
`40pi` rad `s^(-2)`

SOLUTION :`v_(0)=(1800)/(60)=30Hz therefore omega_(0)=2piv_(0)=60pi" rad/s"`
`v=(3000)/(60)=50HZ therefore omega=2piv=100pi""rad/s`
Angular acceleration `a=(omega-omega_(0))/(t)=(100pi-60pi)/(20)=2omega" rad/s"`


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