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A Rough inclined plane with inclination 30^(@) with the horizontal has a block of 1 kg being pushed up the plane by a force of 10 N acting parallel to the plane. If the coefficient of friction between the block and the plane is 0.1 and block is pushed through a distance of 10 m along then incline. What are the increases in the (1) potential energy and (ii) kinetic energy of the block ? |
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Answer» 50 J: 41.3J `DeltaU=mgh` =`1xx10xx5` =50 J…(i) (`because(H)/(10)=sin 30^(@)` and h=5m) COD Also cceleration along the PLANE `a=("Force")/("mass")=([F-mg sin theta+mu mg cos theta])/(m)` =`([10-(10xx1/2+0.1xx10xx(SQRT3)/(2))])/(1)` =`[10-(5+0.5xx1.732)]` =`10-5.87=4.13 ms^(-2)` Applying `v^2-u^2=2 a S` We have `1/2mv^2-1/2mv^2=m a s` `:. DeltaE_k=m a s` =`1xx4.13xx10=41.3 J`...(ii) 
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