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A Rowland ring of mean radius 15 cm has 3500 turns of wire wound on a ferromagnetic core of relative permeability 800. What is the magnetic field vecB in the core for a magnetising current of 1.2 A?

Answer»

Solution :Here R = 15 cm = 0.15 m , N = 3500 , `mu_r =800 , and I = 1.2 A`
`therefore ` Magnetic FIELD in the core of Rowland RING
`B = (mu_0 mu_r NI)/(I) = (mu_0 mu_r N I)/(2pi R)=(4pixx 10^(-7) xx 800xx3500 xx 1.2)/(2pi xx 0.15) = 4.48 T `.


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