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A Rowland ring of mean radius 15 cm has 3500 turns of wire wound on a ferromagnetic core of relative permeability 800. What is the magnetic field B in the core for a magnetising current of 1.2 A? |
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Answer» Mean radius of a Rowland ring, `r=15cm=0.15m` Number of turns on a ferromagnetic core, `N=3500` Relative permeability of the core material, `mu_(r)=800` Magnetising current, `I=1.2A`. The magneic field is given by the relation: `B=(mu_(1)mu_(0)1N)/(2pir)` where, `mu_(0)=` permeabilityof free space=`4nxx10^(-7)Tm A^(-1)` `B=(800xx4pixx10^(-7)xx1.2xx3500)/(2pixx0.15)=4.48T` Therefore, the magnetic field in the core is 4.48T. |
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