InterviewSolution
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InterviewSolution
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A running man has half the KE that a body of half his mass has. The man speeds up by `1.0ms^(-1)` and then has the same energy as the boy. What were the original speeds of the man and the boy?A. `(sqrt2+1),(sqrt2-1)`B. `(sqrt2+1),2(sqrt2+1)`C. `sqrt2,sqrt2`D. `(sqrt2+1),2(sqrt2-1)` |
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Answer» Correct Answer - B (b) According to the question, `(1)/(2) mv_(1)^(2)=(1)/(2)[(1)/(2)xx(m)/(2)xxv_(2)^(2)]` where, `v_(1)="speed of man and "v_(2)`=speed of boy Now, `(1)/(2)m(v_(1)+1)^(2)=(1)/(2)xx(m)/(2)xxv_(2)^(2)` Solving these two equations we get, `v_(1)=(sqrt2+1)ms^(-1)` and `v_(2)=2(sqrt2+1)ms^(-1)` |
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