InterviewSolution
Saved Bookmarks
| 1. |
A sample of 100 g water is slowly heated from `27^@C` to `87^@C`. Calculate the change in the entropy of the water specific heat capacity of water `=4200(J)/(kg-K)` |
|
Answer» `DeltaQ=msDeltaT` `DeltaS=(DeltaQ)/(T)=(msDeltaT)/(T)` The total change in entropy as temperature from `T_1` to `T_2`r `S_1-S_2=int_(T1)^(T2)ms(dT)/(T)` `=msln((T_2)/(T_1))` `=0.1xx4200ln((87+273)/(27+273))` `=420ln(1.2)(J)/(K)` |
|