1.

A sample of 10gm of H_(2) reacts with sufficient amount of oxygen to form 106gm of H_(2)O(l) and H_(2)O_(2)(l). Calculate mass % of H_(2)O.

Answer»

0.679
0.321
0.152
0.848

Solution :ASSUME a mole `H_(2)O`
B mole `H_(2)O_(2)`
`axx18+bxx34=106` . . . (i)
`POAC` on H:
`2xxn_(H_(2))=2xxn_(H_(2)O)+2xxn_(H_(2)O_(2))`
`2XX(10)/(2)=10=2a+2b`
`a+b=5` . . . .(ii)
`18a+18b=90`. . . . . . ..(ii)
`18a+18b=106` . . . . . . .(i)
16b=16
b=1
a=4
Mass of `H_(2)O=axx18`
`=4xx19=72gm`
Mass `% H_(2)O=(72)/(106)xx100=67.9%`


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