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A sample of .^(14)CO_(2) was to be mixed with ordinary .Co_(2) for a biological tracer experiment. In order that 10^(3) cm^(3) of the diluted gas at NTP should have 10^(4) dis/min, how many muCi Of radiocarbon-14 are needed to prepare 60 L ofthe diluted gas ? |
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Answer» SOLUTION :`10 cm^(3)` of the diluted gas at NTP `10^(4)` dis/min `(10^(4))/(60)` DPSL `:.` 60 L (60, 000 `cm^(3)`) of the dilute gas at NTP `(10^(4) xx 60,000)/(60 xx 10)` dps Thus, no of `MU Ci` of `.^(14)CO_(2)` needed `= (10^(4) xx 60,000)/(60 xx 10 xx 3.7 xx 10^(4)) (1 mu Ci = 3.7 xx 10^(4) dps)` `= 27.03 mu Ci` |
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