A sample of 16gr of charcoal was brought into contact with CH_4 gas contained in a vessel of llitre at 27^@C the pressure of gas was found to fall from 760 to 608 torr. The density of charcoal sample is 1.6gr//cm^3. What is the volume of the CH_4 gas adsorbed per gram of the adsorbent at 608 torr and 27^@C

A sample of 16gr of charcoal was brought into contact with CH_4 gas co

1.	A sample of 16gr of charcoal was brought into contact with CH_4 gas contained in a vessel of llitre at 27^@C the pressure of gas was found to fall from 760 to 608 torr. The density of charcoal sample is 1.6gr//cm^3. What is the volume of the CH_4 gas adsorbed per gram of the adsorbent at 608 torr and 27^@C
Answer» 125ml/gr 26ml/gr 16.25ml/gr None Solution :Final volume of gas at 608 torr pressure = `V_2 = (P_1V_1)/(P_2) = (760 xx 1)/(608) = 1.25 (or) V_2 = 1250 ml` volume occupied by gas = volume of vessel-volume occupied by charcoal `= 1000- 16/1.6 = 990 ml`. DIFFERENCE of volume is due to adsoprption of gas by characoal `:.` volume of gas adsorbed by charcoal = `1250 - 990 = 260 ml ` volume of the gas adsorbed per GRAM of characoal = `260/16 = 16.25 ml//gr^(+)` at 608 torr and `27^@C`