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InterviewSolution
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A sample of air turns lime water milky and also turns acidified potassium dichromate green in aqueous solution has low `pH`. This is due to the presence of pollutantsA. `CO_(2)`B. `SO_(2)`C. Both (a) and (b)D. None of these |
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Answer» Correct Answer - B `SO_(2)` turns lime water milky. `SO_(2)` in aquenous solution gives `H_(2)SO_(3)` `H_(2)SO_(3) hArrH^(+)+HSO_(3)^(-)` `CO_(2)` also turns lime water milky. `CO_(2)` in aqueous solution gives `H_(2)SO_(3)` `H_(2)CO_(3)hArrH^(+)+HCO_(3)^(-)` `H_(2)SO_(3)` is stronger acid than `H_(2)CO_(3)`. Thus, ionization of `H_(2)SO_(3)` is larger than `H_(2)CO_(3)`. Thus, `pH` of `H_(2)SO_(3)` is lower than that of `H_(2)CO_(3)` `SO_(2)` also turns acidified `K_(2)Cr_(2)O_(7)` solution green . `3SO_(4)+Cr_(2)O_(7)^(2-)+2H^(+) rarr 3SO_(4)^(2-)+2underset(Green)(Cr^(3+))+H_(2)O`. Thus, air sample has `SO_(2)` as pollutants. |
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