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A sample of diatomic gas with y=1.5 is compressed from a volume of 1600 cc to 400 cc adiabatically. The initial pressure of gas was 1.5xx10^5 Pa.Find the final pressure and work done by the gas in the process. |
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Answer» SOLUTION :We know in an adiabatic process, pressure and volume of gas of its different sates are related as `P_1V_1^gamma=P_2V_2^gamma` or `P_2=(V_1/V_2)^(gamma).P_1` `=(1600/400)^(1.5)xx1.5xx10^5` `=(4)^(1.5)xx1.5xx10^5` `=1.2xx10^6` PA For an adiabatic process work DONE by a gas is given as `W=(P_1V_1-P_2V_2)/(gamma_1)` `=(1.5xx10^5xx1600xx10^(-6)-1.2xx10^6xx400xx10^(-6))/(1.5-1)` `=(240-480)/0.5`=-480 J Here work done by gas comes out a NEGATIVE value thus we can state that as gas is being compressed , work is done on the gas and so work done by gas is -480 J. |
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