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A sample of H_(2)SO_(4) (density 1.787g/mL) is labelled as 86 %by weight . What is the molarity ofacid ? Whatvolume of acid has to be used to make 1 litre of 0.2M H_(2)SO_(4) |
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Answer» Solution :Volume of 100 GM `H_(2)SO_(4) " solution " = 100/(1.787) ` mL ` = 100/(1.787 xx 1000) ` Moles of `H_(2)SO_(4) " in " 100 gm(86)/(98) ` `M_(H_(2)SO_(4)) = 86/(98 xx 100/(1.787 xx 1000)) ` LET V volume of `H_(2)SO_(4)` used to prepare 1 litre of `0.2 MH_(2)SO_(4)` ` :.V xx 15.68 = 1000 xx 0.2rArrV = 12.75 ` mL |
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