1.

A sample of ideal gas is expanded to twice its original volume of `1.00m^3` in a quasi-static process for which `p=alphaV^2`, with `alpha=5.00 atm//m^6`, as shown in Fig. How much work is done by the expanding gas?

Answer» Correct Answer - A
`W=int_(V_i)^(V_f)pdV=int_1^2(alphaV^2)dV`
`=int_1^2(5xx1.01xx10^5)V^2dV`
Solving we get,
`W=1.18xx10^6J`
`=1.18MJ`


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