1.

A sample of NaNO_(3) wwighing 0.38 g is placed in a 50.0 mL measuring flask. The flask is then filled with water upto the mark on the neck. What is the molarity of the solution?

Answer»


SOLUTION :FORMULA mass of `NaNO_(3)=23+14+48=85`
`0.38g NaNO_(3)=23+14+48=85`
`0.38g NaNO_(3)=(0.38)/(85)mol=0.0045mol`
`"MOLARITY of the solution "=(0.0045mol)/(0.050L)=0.090M.`


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