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A sample of of paramagnetic salt contains2.0xx10^(24) atomic dipoles each of dipole moment 1.5xx10^(-23)JT^(-1). The sample is placed under a homogeneous magnetic field of 0.64 T , cooled to a temperature of 4.2 K . The degree of magnetic saturation achieved is equal to 15% . What is the total dipole moment of the sample for a magnetic field of 0.98 T and a temperature of 2.8 K ? (Assume Curie's law) |
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Answer» SOLUTION :`N=2.0xx10^(24) ""m=1.5xx10^(-23)JT^(-1) ""B_("ex")=0.84 T, T = 4.2 K` % saturation = 15% , `sumNm` = ? `=B=0.98T,T =2.8K` Under the initial conditions , the total MAGNETIC moment `=1.5xx10^(-23)xx2.0xx10^(24)xx15/100=4.5JT^(-1)` By Curie law, `M=C.B_0/T "" because m/V=C.(B_0)/T""(m.)/V=C.(B)/(T.)` `:.(m.)/m=B/(T.)xxT/B_0"":.m.=(4.5xx0.98xx4.2)/(2.8xx0.84)=7.9JT^(-1)` |
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