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A satallite of mass `m`, initally at rest on the earth, is launched into a circular orbit at a height equal to the the radius of the earth. The minimum energy required isA. `(sqrt(3))/4 mgR`B. `1/2 mgR`C. `1/4 mgR`D. `3/4 mgR` |
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Answer» Correct Answer - d We know `V_(0)=sqrt((GM)/r) & g=(GM)/(R^(2))` From energy conservation `U_(i)+K_(i)=U_(f)+K_(f)` `-(GMm)/(2R)+1/2m(sqrt((GM)/(2R)))^(2)` `K_(i)=(3GMm)/(4R)impliesK_(i)=3/4 mgR` |
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