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A satellite close to the earth is in orbit above the equator with a period of rotation of `1.5` hours. If it is above a point `P` on the equtor at some time, it will be above `P` again after time ........... |
Answer» Correct Answer - 1.6 hours if it is rotating from west to east `(24)/(17)` hours if it is rotating east to west Relative velocity when satellite revolving anticlockwise `(omega_(1)+omega_(2))t=2piimplies((4pi)/(3)+(2pi)/(24))t=2pi,t=(24)/(17)` if it moves in same direction `((4pi)/(3)-(2pi)/(24))t=2pi` `((30pi)/(24))t=2pi impliest=(24)/(15)=1.6hrs` |
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