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A satellite is orbiting just above the surface of a planet of average density `D` with period `T`. If `G` is the universal gravitational constant, the quantity `(3pi)/G` is equal toA. `T^(2)D`B. `3piT^(2)D`C. `3piD^(2)T`D. `D^(2)T` |
Answer» Correct Answer - A Using `T=2pisqrt((R^(3))/(GM))=2pisqrt((R^(3))/(Gxx4/3piR^(3)D))` `T^(2)=(4pi^(2)R^(3))/(G4/3piR^(3)D)=(3pi)/(DG)rArr (3pi)/G=T^(2)D` |
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