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A satellite is orbiting the earth in an orbit with a velocity `4 km//s`, then the acceleration due to gravity at that height is (in `ms^(-2)`)A. `0.4`B. `0.62`C. `0.87`D. `1.21` |
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Answer» Correct Answer - B `(v_(h))/(v_(s))=sqrt(R/(R+h)), g_(h)=g(R/(R+h))^(2)` |
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