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A satellite of mass `m` is just placed over the surface of earth. In this position mechanical energy of satellite is `E_(1)`. Now it starts orbiting round the earth in a circular path at height `h =` radius of earth. In this position, kinetic energy potential energy and total mechancial energy of satellite are `K_(2)`, `U_(2)` and `E_(2)` respectively. ThenA. `U_(2) = (E_(1))/(2)`B. `E_(2) = (E_(1))/(4)`C. `K_(2) = - E_(2)`D. `K_(2) = - (U_(2))/(2)` |
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Answer» Correct Answer - A::B::C::D `E_(1) = - (GMm)/(R )` `U_(2) = - (GMm)/(2R)` `(r = R + R = 2R)` `K_(2) = (GMm)/(4R)` and `E_(2) = - (GMm)/(4R)` |
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