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A satellite of mass m is orbiting the earth at a height h from its surface. If M is the mass of the earth and R its radius, the kinetic energy of the stellite will beA. `-(GmM)/((R+h)^(2))`B. `(GmM)/(2(R+h)^(2))`C. `(GmM)/((R+h))`D. `(GmM)/(2(R+h))` |
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Answer» Correct Answer - d `K.E.=(1)/(2)mv_(c)^(2)` `=(1)/(2)m(GM)/(r)=(1)/(2)(GMm)/((R+h))` |
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