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A satellite of mass m is revolving round the earth at a height R above surface of earth. If g is gravitational intensity at earth's surface and R is radius of the earth, the K.E. of satellite is : |
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Answer» `"mg" (R )/(4)` `therefore (mv^(2))/(2R)=(GMM)/((2R)^(2)) rArr (1)/(2)mv^(2)=(GMm)/(4R)=(mgR)/(4)` or `K.E.=-(1)/(2) (GP.E.)= -(1)/(2)` `((-GMm)/(2R))=(GMm)/(4R)=(mgR)/(4)` Thus CORRECT choice is (a). |
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