1.

A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is

Answer»

gx
`(gR)/(R-x)`
`(gR^(2))/(R+x)`
`((gR^(2))/(R+x))^(1//2)`

Solution :Gravitational force=centripetal force
`:. (GMm)/((R+x)^(2))=(mv_(0)^(2))/((R+x)) RARR (GM)/((R+x))=v_(0)^(2)`
`rArr v_(0)^(2)=(GM)/((R+x))=(R^(2)g)/((R+x)) rArr v_(0)=[(gR^(2))/((R+x))]^(1//2)`


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