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A satellite of mass m revolves around the earth of radius R at a hight x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite isA. `(gR^2)/(R+x)`B. `(gR)/(R -x)`C. gxD. `((gR^2)/(R +x))^(1//2)` |
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Answer» Correct Answer - D (d) Gravitational force provides the necessary centripetal force. `(mv^2)/((R+x)) = (GmM)/((R + x)^2) also g = (GM)/(R^2)` `:.v^2 = (gR^2)/(R +x) rArr v = ((gR^2)/(R + x))^(1//2)` |
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